Exam JS-Dev-101 Topic 6 Question 20 Discussion
Actual exam question for Salesforce's JS-Dev-101 exam
Question #: 20
Topic #: 6
Question #: 20
Topic #: 6
Given the code below:
const delay = sync delay => {
Return new Promise((resolve, reject) => {
setTimeout (resolve,delay);});};
const callDelay =async () =>{
const yup =await delay(1000);
console.log(1);
What is logged to the console?
const delay = sync delay => {
Return new Promise((resolve, reject) => {
setTimeout (resolve,delay);});};
const callDelay =async () =>{
const yup =await delay(1000);
console.log(1);
What is logged to the console?
Suggested Answer: A Vote an answer
by Ruby at Aug 19, 2026, 05:13 AM
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