Exam H12-811_V2.0 Topic 5 Question 78 Discussion
Actual exam question for Huawei's H12-811_V2.0 exam
Question #: 78
Topic #: 5
Question #: 78
Topic #: 5
What is the broadcast address of the network that contains a host with IP address
192.168.1.147/28?
192.168.1.147/28?
Suggested Answer: C Vote an answer
A /28 subnet mask corresponds to 255.255.255.240, which means each subnet contains 16 IP addresses. The subnet boundaries in the last octet increase in steps of 16: 0, 16, 32, 48, 64, 80,
96, 112, 128, 144, 160, and so on. The host address 192.168.1.147 falls within the subnet range
192.168.1.144 to 192.168.1.159.
In that subnet, the network address is 192.168.1.144, the usable host range is 192.168.1.145 through 192.168.1.158, and the broadcast address is 192.168.1.159. Therefore, option C is correct. Option D is the first usable host address, not the broadcast address.
96, 112, 128, 144, 160, and so on. The host address 192.168.1.147 falls within the subnet range
192.168.1.144 to 192.168.1.159.
In that subnet, the network address is 192.168.1.144, the usable host range is 192.168.1.145 through 192.168.1.158, and the broadcast address is 192.168.1.159. Therefore, option C is correct. Option D is the first usable host address, not the broadcast address.
by Milo at Jul 15, 2026, 04:34 AM
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